Question
Question: Solve the following integral: \(\int{\sin 3x.\cos 2xdx}\)...
Solve the following integral: ∫sin3x.cos2xdx
Solution
Hint: In the above type of integration question, first of all, we will have to convert them by using trigonometric formulae in that form in which we can easily integrate them. So, we have to remember the sine and cosine sum angle formulae given by sin(A−B)=sinAcosB−cosAsinB and sin(A+B)=sinAcosB+cosAsinB.
Complete step-by-step answer:
In the above question, we have to find the integral of sin3x.cos2x which is in the multiplication form and we don’t know the integration of this kind. So, we will try to split it as the sum/difference of sine and cosine.
The formulae of trigonometry that we will use to split the given trigonometric expression as sum/difference of sine and cosine are as shown below;
sin(A+B)=sinAcosB+cosAsinBsin(A−B)=sinAcosB−cosAsinB
So, by using the above formulae we can write the given expression as follows;