Question
Question: Solve the following equation \[2{{\sin }^{2}}\theta =3\cos \theta \], \[0\le \theta \le 2\pi \]....
Solve the following equation 2sin2θ=3cosθ, 0≤θ≤2π.
Explanation
Solution
Hint: In the above equation we will use the trigonometric identity which given as follows:
sin2θ+cos2θ=1
After using the identity, we will solve the quadratic equation in cosθ and we will get the solution for the equation.
Complete Step-by-step answer:
We have been given the equation is 2sin2θ=3cosθ.
As we know that sin2θ=1−cos2θ.
So by using this in the above equation, we get as follows: