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Question

Mathematics Question on Determinants

Solve the equation x+axx xx+ax xxx+a=0\begin{vmatrix} x+a &x &x \\\ x &x+a &x \\\ x&x &x+a \end{vmatrix}=0 , a≠0

Answer

x+axx xx+ax xxx+a=0\begin{vmatrix} x+a &x &x \\\ x &x+a &x \\\ x&x &x+a \end{vmatrix}=0
Applying R1\rightarrowR1+R2+R3, we get:
3x+a3x+a3x+a xx+ax xxx+a=0\begin{vmatrix} 3x+a &3x+a &3x+a \\\ x &x+a &x \\\ x&x &x+a \end{vmatrix}=0

\Rightarrow(3x+a)111 xx+ax xxx+a=0\begin{vmatrix} 1 &1 &1 \\\ x &x+a &x \\\ x&x &x+a \end{vmatrix}=0

Applying C2\rightarrowC2-C1 and C3\rightarrowC3-C1, we have:
(3x+a)100 xa0 x0a\begin{vmatrix} 1&0 &0 \\\ x& a &0 \\\ x&0 &a \end{vmatrix}=0

Expanding along R1,we have:
(3x+a)[1×\timesa2]=0
\Rightarrowa2(3x+a)=0
But a≠0,
Therefore we have
3x+a=0
x=a3\Rightarrow x=-\frac{a}{3}