Question
Mathematics Question on Determinants
Solve the equation x+a x xxx+axxxx+a=0 , a≠0
Answer
x+a x xxx+axxxx+a=0
Applying R1→R1+R2+R3, we get:
3x+a x x3x+ax+ax3x+axx+a=0
⇒(3x+a)1 x x1x+ax1xx+a=0
Applying C2→C2-C1 and C3→C3-C1, we have:
(3x+a)1 x x0a000a=0
Expanding along R1,we have:
(3x+a)[1×a2]=0
⇒a2(3x+a)=0
But a≠0,
Therefore we have
3x+a=0
⇒x=−3a