Question

Solve and check result: $\frac{2x}{3}+1 =\frac{ 7x}{15}+3$

Answer 1

$\frac{2x}{3}+1 =\frac{ 7x}{15}+3$

Transposing $\frac{7x}{15}$ to L.H.S and $1$ to R.H.S, we obtain

$\frac{2x}{3}-\frac{7x}{15}$ = $3-1$

$\frac{5 × 2x - 7x }{ 15}$ = 2

$\frac{3x}{15} = 2$

$\frac{x}{5}$ = 2
Multiplying both sides by $5$, we obtain
$x = 10$
L.H.S = $\frac{2x}{3}+1$

= $\frac{2×10}{3}+1$

= $\frac{2 ×10+1×3}{3}$

= $\frac{23}{3}$

R.H.S = $\frac{7x}{15}+3$

=$\frac{7×10}{15}+3$

= $\frac{7 × 2}{3}+3$

= $\frac{14}{3}+3$

= $\frac{14+3 × 3}{3}$

= $\frac{23}{3}$

L.H.S. = R.H.S.

Hence, the result obtained above is correct