Solveeit Logo

Question

Mathematics Question on Solving Equations having the Variable on both Sides

Solve and check result: 4z+3=6+2z4z + 3 = 6 + 2z

Answer

4z+3=6+2z4z + 3 = 6 + 2z
On transposing 2z2z to L.H.S and 33 to R.H.S, we obtain
4z2z=634z - 2z = 6 - 3
2z=32z = 3
Dividing both sides by 22, we obtain
zz = 32\frac{3}{2}
\Rightarrow L.H.S = 4z+34z + 3
= 4×(32)+34 × (\frac{3}{2}) + 3
=6+36 + 3 = 99
\Rightarrow R.H.S = 6+2z6 + 2z
= 6+2×(32)6 + 2 × (\frac{3}{2})
= 6+3=96 + 3 = 9
L.H.S. = R.H.S.

Hence, the result obtained above is correct.