Question

Solve and check result: $2y+\frac{5}{3}=\frac{26}{3}-y$

Answer 1

$2y+\frac{5}{3}=\frac{26}{3}-y$

Transposing $y$ to L.H.S and $\frac{5}{3}$ to R.H.S, we obtain
$2y+y=\frac{26}{3}-\frac{5}{3}$

$3y$ = $\frac{21}{3}$ = $7$
Dividing both sides by $3$, we obtain

$y$ = $\frac{7}{3}$

L.H.S = $2y+\frac{5}{3}$

=$2×\frac{7}{3}+\frac{5}{3}$

=$\frac{14}{3}+\frac{5}{3}$

=$\frac{19}{3}$

R.H.S = $\frac{26}{3}-y$

=$\frac{26}{3}-\frac{7}{3}$

=$\frac{19}{3}$

L.H.S. = R.H.S.

Hence, the result obtained above is correct.