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Question

Question: Solve- \(4x - 6x \leqslant 7 - 3 - 2x \leqslant 4 \) when \(x\) is an integer....

Solve- 4x6x732x44x - 6x \leqslant 7 - 3 - 2x \leqslant 4 when xx is an integer.

Explanation

Solution

In the given problem, we are asked to solve the equation, since we have one variable it is easy to solve the given equations. We have to find the value of xx. By using the simple concept on the inequalities, which is \geqslant a symbol of greater or equals to sign and \leqslant a symbol of less than equals to sign, which means it is either less than the given values or equals to the given values.

Complete step by step answer:
Since given that the equation
4x6x732x44x - 6x \leqslant 7 - 3 - 2x \leqslant 4 and then we need to find the value of the unknown variable xx for the integer number systems, so we will make use of the basic mathematical operations to simplify further.
Now Turing the variables on the left-hand side and also the numbers on the right-hand side we get 4x6x734x - 6x \leqslant 7 - 3 while changing the values on the equals to, the sign of the values or the numbers will change.
Hence by the addition and subtraction operation, we have, 4x6x732x44x - 6x \leqslant 7 - 3 \Rightarrow - 2x \geqslant 4
Thus, by division, we get 2x4x42x2 - 2x \geqslant 4 \Rightarrow x \geqslant \dfrac{{ - 4}}{2} \Rightarrow x \geqslant - 2
Hence, we have the values as x2x \geqslant - 2
Since the unknown variable xx is given as integer, which means Natural numbers are 1,2,3,...\\{ 1,2,3,...\infty \\} and whole numbers defined as 0,1,2,3,...\\{ 0,1,2,3,...\infty \\} and integers defined as ,...,3,2,1,0,1,2,3,...\\{ - \infty ,..., - 3, - 2, - 1,0,1,2,3,...\infty \\} and the rational and irrational also, hence integers numbers means all should be contained in them, they x2x \geqslant - 2 can be expressed as a integer form of x(2,)x \in ( - 2,\infty ) where the number 22 is at least.

Note:
In the above steps while using the concepts on the inequalities which is the less than or equal to (or) greater than equal to, we might make mistakes when applying it, so learn the concept well.
The other two operations are multiplication and division operations. Since multiplicand refers to the number multiplied. Also, a multiplier refers that multiplies the first number. Have a look at an example; while multiplying 5×75 \times 7the number 55 is called the multiplicand and 4x84x8- 4x \geqslant - 8 \Rightarrow 4x \leqslant 8 \Rightarrowthe number 77 is called the multiplier. Like 2×3=62 \times 3 = 6 or which can be also expressed in the form of 2+2+2(3times)2 + 2 + 2(3times)
The process of the inverse of multiplication method is called division. Like x×y=zx \times y = zis multiplication thus the division sees as x=zyx = \dfrac{z}{y}. Like 4x8x84x24x \leqslant 8 \Rightarrow x \leqslant \dfrac{8}{4} \Rightarrow x \leqslant 2
Hence using simple operations, we solved the given problem.