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Question

Question: Solve \[3\dfrac{1}{2} + 4\dfrac{2}{3}\]...

Solve 312+4233\dfrac{1}{2} + 4\dfrac{2}{3}

Explanation

Solution

To solve this problem, first convert the mixed fraction into fraction. To do that, if we considered the first term 3123\dfrac{1}{2}, to convert this into fraction we need to multiply 33 and 22 we get 66, add this with the number 11 and the answer will be 77, this is our numerator of our required fraction and the denominator will be 22. The required fraction will be 72\dfrac{7}{2}. And repeat the same for the second term too and simplify further more you will get the required answer.

Complete step by step solution:
Let us consider the given question,
312+4233\dfrac{1}{2} + 4\dfrac{2}{3}
To convert this into fraction, first we need to know what is mixed fraction. Mixed fraction is nothing, but the combination of a whole number and the fraction. Let us consider the first term which is 3123\dfrac{1}{2}. Here, 33 is the whole number and 12\dfrac{1}{2} is the fraction. To convert this into fraction follow the three steps given below,
Step: -1 Multiply the whole number and the denominator of the fraction, which is,
3×2=63 \times 2 = 6
Step: -2 Add 66 and 11, which is in the numerator of the fraction. We get
6+1=76 + 1 = 7
Step: -3 77 is the numerator of the required fraction. And the denominator is the denominator of
the given fraction which is 22. And the required fraction is,
312=723\dfrac{1}{2} = \dfrac{7}{2} … (1)
Repeat the step for the second term we get,
423=1434\dfrac{2}{3} = \dfrac{{14}}{3} … (2)
Add (1) and (2), we get
312+423=72+143 3\dfrac{1}{2} + 4\dfrac{2}{3} = \dfrac{7}{2} + \dfrac{{14}}{3}{\text{ }}
Taking L.C.M we get,
312+423=21+286312+423=4963\dfrac{1}{2} + 4\dfrac{2}{3} = \dfrac{{21 + 28}}{6}3\dfrac{1}{2} + 4\dfrac{2}{3} = \dfrac{{49}}{6}
This is our required answer.

Note: To take L.C.M for any two fractions, let’s say 72+143\dfrac{7}{2} + \dfrac{{14}}{3}, consider the denominator of the two fractions which is 22 and 33, now find the least common multiple of both the number which is 66. The LCM is 66.
72+143=7×32×3+14×23×2=21+286=496\dfrac{7}{2} + \dfrac{{14}}{3} = \dfrac{{7 \times 3}}{{2 \times 3}} + \dfrac{{14 \times 2}}{{3 \times 2}} = \dfrac{{21 + 28}}{6} = \dfrac{{49}}{6}
This is our required answer.