Question

Solution of the equation$4.9^{x - 1} = 3\sqrt{(2^{2x + 1})}$ has the solution

• A. 3
• B. 2
• C. 3/2
• D. 2/3

Answer 1

Answer: (C)

3/2

Answer 2

$4.9^{x - 1} = 3.\sqrt{(2^{2x + 1})}$ $\Rightarrow$ $3^{2x - 2 - 1} = 2^{\frac{2x + 1}{2} - 2}$

$\Rightarrow$ $3^{2x - 3} = 2^{\frac{2x - 3}{2}}$ $\Rightarrow$ $2^{\frac{2x - 3}{2}} = \left( 3^{\frac{2x - 3}{2}} \right)^{2}$

$\Rightarrow 2x - 3 = 0$, $\therefore$ $x = \frac{3}{2}$.