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Question

Question: Solution of the equation \(y = x\frac{dy}{dx} + \frac{dx}{dy}\) represents...

Solution of the equation y=xdydx+dxdyy = x\frac{dy}{dx} + \frac{dx}{dy} represents

A

Family of straight lines and a parabola

B

Family of straight lines and a hyperbola

C

family of circles and parabola

D

None

Answer

Family of straight lines and a parabola

Explanation

Solution

Putting dydx=P\frac{dy}{dx} = P we get

y=xP+1Py = xP + \frac{1}{P}

Differentiation w.r.t. to x we get

dydx=P+xdPdx1P2dPdx\frac{dy}{dx} = P + x \cdot \frac{dP}{dx} - \frac{1}{P^{2}}\frac{dP}{dx}

̃ P=P+xdPdx1P2dPdxP = P + x \cdot \frac{dP}{dx} - \frac{1}{P^{2}}\frac{dP}{dx} {dydx=P}\left\{ \because\frac{dy}{dx} = P \right\}

̃ dPdx=0\frac{dP}{dx} = 0 or P2=1xP^{2} = \frac{1}{x}

̃ P = C or (dydx)2=1x\left( \frac{dy}{dx} \right)^{2} = \frac{1}{x}

Put these value in given equation we get y=Cx+1Cy = Cx + \frac{1}{C} which is equation of family of straight lines &

y2=(Px+1P)2=P2x2+2x+1P2y^{2} = \left( Px + \frac{1}{P} \right)^{2} = P^{2}x^{2} + 2x + \frac{1}{P^{2}}

Put value of P2 we get

y2 = x + 2x + x = 4x

which is a singular solution and it represents parabola