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Question: Solubility product of a sulphide MS is \(3 \times 10^{- 25}\)and that of another sulphide NS is \(4 ...

Solubility product of a sulphide MS is 3×10253 \times 10^{- 25}and that of another sulphide NS is 4×10404 \times 10^{- 40}. In ammoniacal solution.

A

Only NS gets precipitated

B

Only MS gets precipitated

C

No sulphide precipitates

D

Both sulphides precipitate

Answer

Both sulphides precipitate

Explanation

Solution

The concentration of S2S^{2 -}ions in group II is lowered by maintaining acidic medium in the presence of NH4ClNH_{4}Cl. The ionization of H2SH_{2}S is supressed due to common ion effect. So the ionic product is less than solubility product.