Question
Question: Solubility product of a sulphide MS is \(3 \times 10^{- 25}\)and that of another sulphide NS is \(4 ...
Solubility product of a sulphide MS is 3×10−25and that of another sulphide NS is 4×10−40. In ammoniacal solution.
A
Only NS gets precipitated
B
Only MS gets precipitated
C
No sulphide precipitates
D
Both sulphides precipitate
Answer
Both sulphides precipitate
Explanation
Solution
The concentration of S2−ions in group II is lowered by maintaining acidic medium in the presence of NH4Cl. The ionization of H2S is supressed due to common ion effect. So the ionic product is less than solubility product.