Solubility of (Ca\_3(PO\_4)2) in (100) (mL) of pure water is... | Chemistry | SolveeIt | Solveeit

Today, August 24

Question

Solubility of $Ca_3(PO_4)_2$ in $100$ $mL$ of pure water is $W$ gm. Find out $K_{sp}$ of $Ca_3(PO_4)_2$ is: (M: Molecular mass of $Ca_3(PO_4)_2$ )

A

$108 \times \bigg(\frac{W}{M}\bigg)^5$

B

$108 \times 105 \times \bigg[\frac{W}{M}\bigg]^5$

C

$108 \times 104 \times \bigg[\frac{W}{M}\bigg]^5$

D

$108 \times 106 \times \bigg[\frac{W}{M}\bigg]^5$

Answer

$108 \times 105 \times \bigg[\frac{W}{M}\bigg]^5$

Explanation

Solution

The correct option is (B): $108 \times 105 \times \bigg[\frac{W}{M}\bigg]^5$