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Question

Chemistry Question on Solubility Equilibria Of Sparingly Soluble Salts

Solubility of AgClAgCl will be minimum in

A

0.01 M NaCl0.01\,M\,NaCl solution

B

0.01 M CaCl20.01\,M\,CaCl_{2} solution

C

pure water

D

0.001 M AgNO30.001\,M\,AgNO_{3} solution

Answer

0.01 M CaCl20.01\,M\,CaCl_{2} solution

Explanation

Solution

CaCl2+Ca2++2Cl−CaCl_{2}+Ca^{2+}+2Cl^{-} CaCl2CaCl_{2} in solution is dissociated into 33 ions (maximum). Due to common ions effect solubility of AgClAgCl will be minimum in 0.01 M CaCl20.01\,M\, CaCl_{2} solution.