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Question: Solubility of a solute is S. Find its percentage by weight: A. \(\dfrac{{200S}}{{S + 100}}\) B....

Solubility of a solute is S. Find its percentage by weight:
A. 200SS+100\dfrac{{200S}}{{S + 100}}
B. 50SS+100\dfrac{{50S}}{{S + 100}}
C. 100SS+100\dfrac{{100S}}{{S + 100}}
D. None of these

Explanation

Solution

Solubility of a solute is given by S. It means that S g solute is present in 100 g solution. The total mass of the solution gives how much solute is dissolved in a certain amount of solvent.

Complete answer:
Solubility is a property referring to the ability for a given substance, the solute, to dissolve in a solvent. The mass/mass percent (% m/m) is defined as the mass of a solute divided by the mass of a solution times 100. It is measured in terms of the maximum amount of solute dissolved in a solvent at equilibrium. The relation between the solute and solvent is very important in determining solubility. Strong solute-solvent attractions equate to greater solubility while weak solute-solvent attractions equate to lesser solubility. polar solutes tend to dissolve best in polar solvents while non-polar solutes tend to dissolve best in non-polar solvents.
If the solubility is SS , there are SS g solute in 100g100g Solvent.
Total mass of solution =(S+100)g = (S + 100)g
%bymass=massofsolutemassofsolution×100%\% \,by \,mass = \dfrac{{mass \,of \,solute}}{{mass \,of \,solution}}\times100\%
=Sg(S+100)g×100= \dfrac{{Sg}}{{(S + 100)g}}\times100
% by mass =100S100+S = \dfrac{{100S}}{{100 + S}}

**Therefore the correct option is option C.

Note:**
A concentrated solution is one in which there is a large amount of solute in a given amount of solvent. A dilute solution is one in which there is a small amount of solute in a given amount of solvent. At a given temperature the solubility product is constant. Lesser the value of solubility product indicates lower solubility and higher value of solubility product indicates greater solubility.