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Question

Physics Question on Acceleration

solid sphere is rolling purely with speed v on horizontal surface. It rolls up an incline surface and stops at height h. Then height h is [g is the acceleration due to gravity]:

A

3v210g\frac{3 v^2}{10} g

B

7v210g\frac{7 v^2}{10} g

C

5v27g\frac{5v^2}{7} g

D

7v25g\frac{7v^2}{5} g

Answer

7v210g\frac{7 v^2}{10} g

Explanation

Solution

The correct option is (B): 7v210g\frac{7 v^2}{10} g