Physics Question on Moment Of Inertia

Question

Solid sphere $A$ is rotating about an axis $PQ$ If the radius of the sphere is $5 cm$ then its radius of gyration about $PQ$ will be $\sqrt{x} cm$ The value of $x$ is __
Solid sphere A is rotating about an axis PQ.If the radius of the sphere is 5cm then its radius of gyration about PQ will be √xcm.The value of x is

Accepted Answer

The correct answer is 110
Icm=52MR2
IPQ=Icm+md2
IPQ=52mR2+m(10cm)2
For radius of gyration
IPQ=mk2
k2=52R2+(10cm)2
=52(5)2+100
=10+100=110
k=110cm
x=110