Question

Sodium peroxide which is a yellow solid, when exposed to air becomes white due to the formation of

• A. ${{H}_{2}}{{O}_{2}}$
• B. $N{{a}_{2}}O$
• C. $N{{a}_{2}}O$ and ${{O}_{3}}$
• D. $NaOH$ and $N{{a}_{2}}C{{O}_{3}}$

Answer 1

Answer: (D)

$NaOH$ and $N{{a}_{2}}C{{O}_{3}}$

Answer 2

Sodium peroxide reacts with moisture and $C{{O}_{2}}$ of air (when exposed to air) and becomes white due to the formation of $NaOH$ and $N{{a}_{2}}C{{O}_{3}}$ $2N{{a}_{2}}{{O}_{2}}+2{{H}_{2}}O\xrightarrow{{}}4NaOH+{{O}_{2}}$ $2NaOH+C{{O}_{2}}\xrightarrow{{}}N{{a}_{2}}C{{O}_{3}}+{{H}_{2}}O$