Question

${SnCl2 + 2HgCl2 -> }$ $\underset{\text{White ppt.}}{ {(A)}}$ ${(A) + SnCl2 -> }$ $\underset{\text{Grey}}{ {(B)}}$ A and B are

• A. $HgCl_4,\, Hg$
• B. $Hg_2Cl_2,\, Hg$
• C. $SnCl_4,\, Sn$
• D. $Sn_2Cl_2, \,Sn$

Answer 1

Answer: (B)

$Hg_2Cl_2,\, Hg$

Answer 2

${SnCl2 + 2HgCl2 -> Hg2Cl2 + }$ $\underset{\text{White ppt.}}{ {SnCl4}}$ ${Hg2Cl2 + SnCl2 -> 2Hg + }$ $\underset{\text{Grey}}{ {SnCl4}}$