Question

Smallest internuclear distance is found in

• A. $O _{2}$
• B. $O _{2}^{+2}$
• C. $O _{2}^{-}$
• D. $O _{2}^{-2}$

Answer 1

Answer: (B)

$O _{2}^{+2}$

Answer 2

In $O _{2}$, the bond order $=2$ In $O _{2}^{+}$, the bond order $=2.5$ In $O _{2}^{-}$, the bond order $=1.5$ In $O _{2}^{-2}$, the bond order $=1$ As the bond order in $O _{2}{ }^{+}$ is highest, so its internuclear distance is smallest.