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Question: Sketch the graph for \( y = {\tan ^{ - 1}}(\tan x) \)...

Sketch the graph for y=tan1(tanx)y = {\tan ^{ - 1}}(\tan x)

Explanation

Solution

To sketch the graph of y=tan1(tanx)y = {\tan ^{ - 1}}(\tan x) . First, we have to calculate the domain and range of tanx and tan1{\tan ^{ - 1}} . From this, we can sketch the graph of tanx\tan x and tan1{\tan ^{ - 1}} . With the help of these, we can draw a graph of y=tan1(tanx)y = {\tan ^{ - 1}}(\tan x)
In a relation R from set A to set B, the set of all first components of order pair belongings to R is called the domain and all the second element of pair is called range.

Complete step by step solution:
We know that the domain of tan. function(tangent function) is the set \left\\{ {x:x \in R,and.x \ne (2n + 1)\dfrac{\pi }{2},n \in Z} \right\\}
here R represents the real number and x(2n+1)π2x \ne (2n + 1)\dfrac{\pi }{2} means the domain of tan function does not contain an odd multiple of π2\dfrac{\pi }{2} . nZn \in Z Represents that n is an integer. Z is the symbol of an integer.
The range of the tan function in R. Here R represents the real number. If we restrict the domain of a tangent function to (π2,π2)\left( {\dfrac{{ - \pi }}{2},\dfrac{\pi }{2}} \right) then it is one-one and onto with the range R. So, the tangent function is restricted to any of interval etc, is bijective and range is R. SO, tan1{\tan ^{ - 1}} can be defined as the function whose domain is R and range could be any of interval (3π2,π2),(π2,π2),(π2,3π2)\left( {\dfrac{{ - 3\pi }}{2},\dfrac{\pi }{2}} \right),\left( {\dfrac{{ - \pi }}{2},\dfrac{\pi }{2}} \right),\left( {\dfrac{\pi }{2},\dfrac{{3\pi }}{2}} \right) and so on. This interval gives different branches of the function tan1{\tan ^{ - 1}} . The branch (π2,π2)\left( {\dfrac{{ - \pi }}{2},\dfrac{\pi }{2}} \right) is called the principal value branch of the function tan1{\tan ^{ - 1}} therefor tan1:R(π2,π2){\tan ^{ - 1}}:R \to \left( {\dfrac{{ - \pi }}{2},\dfrac{\pi }{2}} \right)

The graph of a tan function y=tanxy = \tan x is given as:

The graph of y=tan1xy = {\tan ^{ - 1}}x is given as

As y=tan1(tanx)y = {\tan ^{ - 1}}(\tan x) is periodic with period π. therefore to draw this graph we should draw the graph for one interval π\pi and repeat for the entire value.
As we know that y=tan1(tanx)y = {\tan ^{ - 1}}(\tan x) = \left\\{ {x:\dfrac{\pi }{2} < x < \dfrac{\pi }{2}} \right\\}
This has been defined for π2<x<π2\dfrac{\pi }{2} < x < \dfrac{\pi }{2} that has a length π\pi so its graph could be plotted as

Thus this graph of y where y is not defined for x(2n+1)π2x \in (2n + 1)\dfrac{\pi }{2} .

Note:
One-one function: A function f:xyf:x \to y is defined as a one-one function of the image of distinct elements of X under ff are distinct.
Onto function: A function is f:xyf:x \to y said to be onto the function of every element of Y is an image of some element of X under f.
Bijective Function: The function which is both one-one and onto is called the bijective function.