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Question

Question: Sketch the angle in standard position \( \dfrac{{ - 23\pi }}{3} \) ....

Sketch the angle in standard position 23π3\dfrac{{ - 23\pi }}{3} .

Explanation

Solution

Hint : In this problem, we have given a value of angle in radians and we have to sketch the angle given in standard position and we know that in angles, the angle starts from 0 and π=180\pi = 180^\circ and there are four quadrants where an angle is formed. If the angle is formed from initial side rotating in counter clockwise then the measure of the angle is positive and if the angle is formed from initial side rotating in clockwise then the measure of the angle is negative.

Complete step-by-step answer :
In this problem we have to sketch an angle whose measure is negative, so, we have to rotate clockwise to form the angle. We know that, one whole round is of 360360^\circ or we can say, it is of 2π2\pi , so a half round is of π\pi .

Now, we will convert the given angle in mixed fraction, 23π3=72π3- \dfrac{{23\pi }}{3} = - 7\dfrac{{2\pi }}{3} , from this we have 7π7\pi , now, firstly we will move upto 7π7\pi and then, make an angle for 2π3\dfrac{{2\pi }}{3} . We know that, one half round is π\pi and now we have to complete 7π7\pi .

Now, we have to make an angle of 2π3\dfrac{{2\pi }}{3} from 7π7\pi and when we convert 2π3\dfrac{{2\pi }}{3} into degrees, we get,
2×1803=120\dfrac{{2 \times 180}}{3} = 120^\circ and now, we have to make an angle of 120120^\circ from 7π7\pi and we know that one-fourth round is of 9090^\circ , after forming an angle of 9090^\circ from 7π7\pi , we have to make an angle of 3030^\circ ,as, 90+30=12090 + 30 = 120^\circ . Now, we have sketched an angle in standard position.

Note : When an angle is formed there are two sides, one is initial side, from the where the angle formation starts and the other one is terminal side, which can be reached from the initial side with a rotation and when an angle with a measure is formed then that position is termed as standard position of an angle.