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Question: Six identical uniform rods PQ, QR, RS, ST, TU and UP each weighing W are freely joined at their ends...

Six identical uniform rods PQ, QR, RS, ST, TU and UP each weighing W are freely joined at their ends to form a hexagon. The rod PQ is fixed in a horizontal position and middle points of PQ and ST are connected by a vertical string. The tension in string is

A

W

B

3W

C

2W

D

4W

Answer

3W

Explanation

Solution

Let a small displacement be given to the system in vertical plane in frame such that ST remains horizontal then let vertical displacement of centres of rods UP and QR be y then vertical displacement of centres of UT and RS will be 3y and that of TS will by 4y. Equating the total virtual work to zero we get

(W + W)δy + (W + W)3δy + W(4δy) – T(4δy) = 0

(where T is the lension in thread)

or 2W + 6 W + 4W = 4T

or T = 3W