Question

Six coins tossed simultaneously then find the probability of getting at least 4 heads.

Answer 1

To find the probability of getting at least 4 heads when tossing six coins simultaneously, we need to calculate the probability of getting 4, 5, or 6 heads and add them together.

Probability of getting 4 heads: The number of ways to choose 4 heads out of 6 coins can be calculated as: C(6, 4) = 6! / (4!(6 - 4)!) = 15

Probability of getting 5 heads: The number of ways to choose 5 heads out of 6 coins can be calculated as: C(6, 5) = 6! / (5!(6 - 5)!) = 6

Probability of getting 6 heads: The number of ways to choose 6 heads out of 6 coins can be calculated as: C(6, 6) = 6! / (6!(6 - 6)!) = 1

Now, let's calculate the probabilities for each case:

Probability of getting 4 heads: 15/64

Probability of getting 5 heads: 6/64

Probability of getting 6 heads: 1/64

To find the probability of getting at least 4 heads, we add these probabilities together:

Probability of getting at least 4 heads = (15 + 6 + 1) / 64 = 22 / 64 = 11 / 32

Hence, the probability of getting at least 4 heads when six coins are tossed simultaneously is 11/32 or approximately 0.34375, which is approximately 34.375%.