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Question

Physics Question on electrostatic potential and capacitance

Six capacitors each of capacitance of 2μF2 \mu F are connected as shown in the figure. The effective capacitance between A and B is

A

12μF12 \mu F

B

8/3μF8/3 \mu F

C

3μF3 \mu F

D

6μF6 \mu F

Answer

12μF12 \mu F

Explanation

Solution

All the capacitors are connected in parallel.
Therefore, the effective capacitance between A and B
=6C=6×2=12μF= 6C = 6 \times 2 = 12 \mu F