Question

Six boys and six girls sit in a row randomly. Probability that boys and girls sit alternatively is

• A. $\frac { 1 } { 231 }$
• B. $\frac { 5 } { 462 }$
• C. $\frac { 1 } { 462 }$
• D. $\frac { 7 } { 101 }$

Answer 1

Answer: (C)

$\frac { 1 } { 462 }$

Answer 2

Total number of ways = \begin{tabular} { | l } 12 \ \hline \end{tabular}