Question

Six boys and six girls sit along a line alternatively with

probability p₁ and along a circle (again alternatively) with

probability p₂, then p₁/p₂ is equal to

• A. 1
• B. 1/5
• C. 6
• D. None of these

Answer 1

Answer: (A)

1

Answer 2

P₁ = $\frac { ( 6 ! ) \times ( 6 ! ) \times ( 2 ! ) } { ( 12 ) ! }$ straight line

P₂= $\frac { ( 6 ! ) \times ( 6 ! ) \times ( 2 ! ) } { ( 12 ! ) ( 5 ! ) ( 6 ! ) } \times ( 11 ! )$= 1