Solveeit Logo

Question

Question: Sinx graph...

Sinx graph

Answer

The graph of y=sinxy = \sin x is a continuous wave with a domain of all real numbers and a range of [1,1][-1, 1]. It has a period of 2π2\pi, repeating its pattern every 2π2\pi units. Key points include (0,0)(0, 0), (π2,1)(\frac{\pi}{2}, 1), (π,0)(\pi, 0), (3π2,1)(\frac{3\pi}{2}, -1), and (2π,0)(2\pi, 0).

Explanation

Solution

The graph of y=sinxy = \sin x is a fundamental trigonometric function characterized by its wave-like shape.

  1. Domain: The sine function is defined for all real numbers, so its domain is R\mathbb{R} (all real numbers).
  2. Range: The output values of the sine function oscillate between -1 and 1, inclusive. Thus, the range is [1,1][-1, 1].
  3. Periodicity: The sine function is periodic with a period of 2π2\pi. This means the graph repeats its pattern every 2π2\pi units along the x-axis.
  4. Key Points for One Cycle (0 to 2π2\pi):
    • At x=0x=0, sin(0)=0\sin(0) = 0. The graph passes through the origin (0,0)(0,0).
    • At x=π2x=\frac{\pi}{2}, sin(π2)=1\sin(\frac{\pi}{2}) = 1. This is the maximum value, occurring at (π2,1)(\frac{\pi}{2}, 1).
    • At x=πx=\pi, sin(π)=0\sin(\pi) = 0. The graph crosses the x-axis at (π,0)(\pi, 0).
    • At x=3π2x=\frac{3\pi}{2}, sin(3π2)=1\sin(\frac{3\pi}{2}) = -1. This is the minimum value, occurring at (3π2,1)(\frac{3\pi}{2}, -1).
    • At x=2πx=2\pi, sin(2π)=0\sin(2\pi) = 0. The graph completes one cycle and returns to the x-axis at (2π,0)(2\pi, 0).

The graph is a smooth, continuous curve that connects these key points and extends infinitely in both the positive and negative x-directions, repeating the same wave pattern.