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Question

Question: \(\sin x + c\)...

sin⁡x+c\sin x + c

A

cos⁡x+c\cos x + c

B

x+cx + c

C

x2+cx^{2} + c

D

∫x−1(x+1)2 6mudx=\int_{}^{}{\frac{x - 1}{(x + 1)^{2}}\mspace{6mu} dx =}

Answer

x+cx + c

Explanation

Solution

∫tan⁡(3x−5)sec⁡(3x−5) 6mudx=\int_{}^{}{\tan(3x - 5)\sec(3x - 5)\mspace{6mu} dx =}

sec⁡(3x−5)+c\sec(3x - 5) + c

13sec⁡(3x−5)+c\frac{1}{3}\sec(3x - 5) + c