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Question

Question: \(\sin x - \frac{2}{3}\sin^{3}x + \frac{1}{5}\sin^{5}x + c\)...

sinx23sin3x+15sin5x+c\sin x - \frac{2}{3}\sin^{3}x + \frac{1}{5}\sin^{5}x + c

A

sinx+23sin3x+15sin5x+c\sin x + \frac{2}{3}\sin^{3}x + \frac{1}{5}\sin^{5}x + c

B

sinx23sin3x15sin5x+c\sin x - \frac{2}{3}\sin^{3}x - \frac{1}{5}\sin^{5}x + c

C

secxtan3x6mudx=\int_{}^{}{\sec x\tan^{3}x\mspace{6mu} dx =}

D

None of these

Answer

sinx+23sin3x+15sin5x+c\sin x + \frac{2}{3}\sin^{3}x + \frac{1}{5}\sin^{5}x + c

Explanation

Solution

Put 16log[sec6x+tan6x]+c\frac{1}{6}\log\lbrack\sec 6x + \tan 6x\rbrack + c then

log[sec6x+tan6x]+c\log\lbrack\sec 6x + \tan 6x\rbrack + c