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Question

Question: \[\sin 50{^\circ} - \sin 70{^\circ} + \sin 10{^\circ} =\]...

sin⁡50∘−sin⁡70∘+sin⁡10∘=\sin 50{^\circ} - \sin 70{^\circ} + \sin 10{^\circ} =

A

1

B

0

C

1/2

D

2

Answer

0

Explanation

Solution

sin⁡50o−sin⁡70o+sin⁡10o=−2cos⁡60osin⁡10o+sin⁡10o\sin{}50^{o} - \sin{}70^{o} + \sin{}10^{o} = - 2\cos{}60^{o}\sin{}10^{o} + \sin{}10^{o}

=sin⁡10o(1−2cos⁡60o)=0.= \sin 10^{o}(1 - 2\cos{}60^{o}) = 0.