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Question

Question: \[\sin^{- 1}x + c\]...

sin⁡−1x+c\sin^{- 1}x + c

A

12ln⁡∣1+x1−x∣+c\frac{1}{2}\ln\left| \frac{1 + x}{1 - x} \right| + c

B

12ln⁡∣1−x1+x∣+c\frac{1}{2}\ln\left| \frac{1 - x}{1 + x} \right| + c

C

∫dx4x2+9=\int_{}^{}{\frac{dx}{4x^{2} + 9} =}

D

None of these

Answer

∫dx4x2+9=\int_{}^{}{\frac{dx}{4x^{2} + 9} =}

Explanation

Solution

Put [tan⁡−1x2]2+c\lbrack\tan^{- 1}x^{2}\rbrack^{2} + c

12[tan⁡−1x2]2+c\frac{1}{2}\lbrack\tan^{- 1}x^{2}\rbrack^{2} + c.