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Question: Simplify the given logarithmic functions: log (ab) – log |b| (A). log a (B). log |a| (C). -lo...

Simplify the given logarithmic functions: log (ab) – log |b|
(A). log a
(B). log |a|
(C). -log a
(D). None of these

Explanation

Solution

Start by simplifying the relation by using the logarithmic properties and rearrange the like terms . Then look for all the possible cases of |b| and solve by substituting those values in the equation, We’ll get the answer.

Complete step-by-step answer :
Given
log(ab)logb\log (ab) - \log \left| b \right|
By using the property of logarithmic functions i.e. logxlogy=logxy\log x - \log y = \log \dfrac{x}{y} . We get , logabb\log \dfrac{{ab}}{{\left| b \right|}}
Now, The equation can also be written as
logabbeqn(1)\log a \cdot \dfrac{b}{{\left| b \right|}} \to eqn(1)
Now, We’ll solve for all the possible cases for bb\dfrac{b}{{\left| b \right|}}
Case 1: b=b\left| b \right| = b
Then , the value of bb\dfrac{b}{{\left| b \right|}} will be +1
Case 2: b=b\left| b \right| = - b
Then , the value of bb\dfrac{b}{{\left| b \right|}} will be bb=1\dfrac{b}{{ - b}} = - 1
Now ,Equation 1 can be written as
loga(1) and loga(1)\log a \cdot (1){\text{ and }}\log a \cdot ( - 1)
Which gives us two values loga and log(a)\log a{\text{ and }}\log ( - a) , and can be represented as loga\log \left| a \right|
Therefore, the answer is loga\log \left| a \right|.
So , option B is the correct answer.

Note :All the properties of logarithmic functions must be well known and practised in order to solve such similar questions. Some other functions such as the G.I.F.( Greatest Integer Function) and Modulus function etc must also be known , as a combination of such functions can be asked.