Question
Question: Simplify the following using identities. a.\[{\left( {109} \right)^2} + {\left( {91} \right)^2}\] ...
Simplify the following using identities.
a.(109)2+(91)2
b.(200)2−(100)2
c.(1025)2−(975)2
d.(10)2+(20)2
Solution
Firstly, observe the question and then use the identity (a+b)2+(a−b)2=2[a2+b2] , a2−b2=(a−b)(a+b) , (a+b)2−(a−b)2=4ab , a2+b2=(a+b)2−2ab . With the formula we can easily simplify this equation by knowing all the variables i.e a and b.
Formula Used: Here, we can use the formula according to the requirement of the question(a+b)2+(a−b)2=2[a2+b2] , a2−b2=(a−b)(a+b) , (a+b)2−(a−b)2=4ab , a2+b2=(a+b)2−2ab
Complete step-by-step answer:
Now, we will begin with:
(a)(109)2+(91)2
First, split 109 and 91 in factors of 100.
⇒(100+9)2+(100−9)2
Here, it becomes an identity (a+b)2+(a−b)2=2[a2+b2]
Now considering left hand side , {\left( {a + b} \right)^2} + {\left( {a - b} \right)^2} = $$$${\left( {100 + 9} \right)^2} + {\left( {100 - 9} \right)^2}
From here, we can clearly see that a=100 and b=9 .
Put the values of a and b in right hand side of formula ⇒2[a2+b2]
⇒2[(100)2+(9)2]
By opening the squares:
⇒2[10000+81]
On further simplifying:
⇒2[10081]
We get, ⇒20162
{\left( {109} \right)^2} + {\left( {91} \right)^2}$$$$ \Rightarrow 20162
(b)(200)2−(100)2
As, it is clearly visible that is a2−b2 and hence we can use the identity a2−b2=(a−b)(a+b) .
Now considering left hand side , {a^2} - {b^2}$$$$ = {\left( {200} \right)^2} - {\left( {100} \right)^2}
From here, we can clearly see that a=200 and b=100 .
Put the values of a and b in right hand side of formula ⇒(a−b)(a+b)
⇒(200−100)(200+100)
On simplifying:
⇒100∗300
We get, ⇒30000
{\left( {200} \right)^2} - {\left( {100} \right)^2}$$$$ \Rightarrow 30000
(c)(1025)2−(975)2
First, of all split 1025 and 975 in factors of 1000.
⇒(1000+25)2−(1000−25)2
Here, it becomes an identity (a+b)2−(a−b)2=4ab
Now considering left hand side , {\left( {a + b} \right)^2} - {\left( {a - b} \right)^2} = $$$${\left( {1000 + 25} \right)^2} + {\left( {1000 - 25} \right)^2}
From here, we can clearly see that a=1000 and b=25 .
Put the values of a and b in right hand side of formula ⇒4ab
⇒4∗1000∗25
By multiplying:
⇒100000
{\left( {1025} \right)^2} - {\left( {975} \right)^2}$$$$ \Rightarrow 100000
(d)(10)2+(20)2
As, it is clearly visible that is a2+b2 and hence we can use the identity a2+b2=(a+b)2−2ab
Now considering left hand side , {a^2} + {b^2}$$$$ = {\left( {10} \right)^2} + {\left( {20} \right)^2}
From here, we can clearly see that a=10 and b=20 .
Put the values of a and b in right hand side of formula =(a+b)2−2ab
⇒(10+20)2−2∗10∗20
⇒(30)2−2∗10∗20
On simplifying square,
⇒900−2∗10∗20
And on multiplying,
⇒900−400
We get, ⇒500
{\left( {10} \right)^2} + {\left( {20} \right)^2}$$$$ \Rightarrow 500
Note: In this type of question, first of all observe the given statements and calculate the values. Accordingly, implement the identities which are most appropriate.