Solveeit Logo

Question

Mathematics Question on Laws of Exponents for Real Numbers

Simplify : (i) 2 23\frac{2}{3} . 2 15\frac{1}{5} (ii) (133\frac{1}{33})7 (iii) 11 12\frac{1}{2} / 1114\frac{1}{4} (iv) 7 12\frac{1}{2} . 8 12\frac{1}{2}

Answer

(i) 2 23\frac{2}{3} . 2 15\frac{1}{5}= 2( 23\frac{2}{3} + 15\frac{1}{5})

= 2 1315\frac{13}{15}

(ii) (133\frac{1}{33})7 = (3-3)7

= (3)-21

(iii) 11121114 \frac{11\frac{1}{2}}{ 11\frac{1}{4}}

=1114\frac{1}{4}

(iv) 7 12\frac{1}{2} . 8 12\frac{1}{2}

= (56) 12\frac{1}{2}