Question

Simplify $\cos ec\left( x \right) \times (\sin x + \cos x)$.

Answer 1

The given question deals with basic simplification of trigonometric functions by using some of the simple trigonometric formulae such as $\cos ec(x) = \dfrac{1}{{\sin (x)}}$ and $\cot (x) = \dfrac{{\cos (x)}}{{\sin (x)}}$. Basic algebraic rules and trigonometric identities are to be kept in mind while doing simplification in the given problem.

Complete step-by-step solution:
In the given problem, we have to simplify the product of $\cos ec(x)$ and $[\sin (x) + \cos (x)]$.
So, $\cos ec(x) \times (\sin x + \cos x)$
Using $\cos ec(x) = \dfrac{1}{{\sin (x)}}$,
$=$ $\dfrac{1}{{\sin x}} \times \left( {\sin x + \cos x} \right)$
On opening brackets and simplifying, the denominator $\sin (x)$ gets distributed to both the terms. So, we get,
$=$ $\dfrac{{\sin x}}{{\sin x}} + \dfrac{{\cos x}}{{\sin x}}$
Now, cancelling the numerator and denominator in the first term, we get,
$=$ $\left( {1 + \dfrac{{\cos (x)}}{{\sin (x)}}} \right)$
Now, using $\cot (x) = \dfrac{{\cos (x)}}{{\sin (x)}}$ , we get,
$=$ $(1 + \cot x)$
Hence, the product $\cos ec\left( x \right) \times (\sin x + \cos x)$can be simplified as $(1 + \cot x)$ by the use of basic algebraic rules and simple trigonometric formulae.

Note: Trigonometric functions are also called Circular functions. Trigonometric functions are the functions that relate an angle of a right angled triangle to the ratio of two side lengths. There are $6$ trigonometric functions, namely: $\sin (x)$,$\cos (x)$,$\tan (x)$,$\cos ec(x)$,$\sec (x)$and $\cot \left( x \right)$ . Also, $\cos ec(x)$ ,$\sec (x)$and $\cot \left( x \right)$ are the reciprocals of $\sin (x)$,$\cos (x)$ and $\tan (x)$ respectively.