Question

Simplify and solve the linear equation $0.25(4f-3)=0.05(10f-9)$

Answer 1

$0.25(4f-3)=0.05(10f-9)$

$\frac{1}{4}(4f-3)=\frac{1}{20}(10f-9)$

Multiplying both sides by $20$, we obtain
$5(4f - 3) = 10f - 9$
$\Rightarrow$ $20f - 15 = 10f - 9$ (Opening the brackets)
$\Rightarrow$ $20f - 10f = - 9 + 15$
$\Rightarrow$ $10f = 6$
$\Rightarrow$ $f = \frac{3}{5}$
$=0.6$