Question
Question: \(\sim(p \Leftrightarrow q)\) is...
∼(p⇔q) is
A
∼p6mu∧∼q
B
∼p6mu∨∼q
C
(p6mu∧∼q)∨(∼p6mu∧q)
D
None of these
Answer
(p6mu∧∼q)∨(∼p6mu∧q)
Explanation
Solution
∼(p⇔q)=(p6mu∧∼q)∨(q6mu∧∼p).
∼(p⇔q) is
∼p6mu∧∼q
∼p6mu∨∼q
(p6mu∧∼q)∨(∼p6mu∧q)
None of these
(p6mu∧∼q)∨(∼p6mu∧q)
∼(p⇔q)=(p6mu∧∼q)∨(q6mu∧∼p).