Sides of a triangle are AB = 9, BC = 7, AC = 8. Then cos 3C... | Mathematics | SolveeIt | Solveeit

Today, August 20

Question

Sides of a triangle are AB = 9, BC = 7, AC = 8. Then cos 3C equals to

A

$\frac{-262}{343}$

B

$\frac{181}{247}$

C

$\frac{81}{93}$

D

$\frac{-283}{285}$

Answer

$\frac{-262}{343}$

Explanation

Solution

The Correct answer is option is (A) : $\frac{-262}{343}$