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Question

Question: SI unit of permittivity is...

SI unit of permittivity is

A

(a) C2m2N1C^{2}m^{2}N^{- 1}

A

(b) C1m2N2C^{- 1}m^{2}N^{- 2}

A

(c) C2m2N2C^{2}m^{2}N^{2}

A

(d) C2m2N1C^{2}m^{- 2}N^{- 1}

Explanation

Solution

(d)

Sol. F=14πq1q2r2=14πq1q2Fr2=C2m2N1F = \frac{1}{4\pi \in}\frac{q_{1}q_{2}}{r^{2}} \Rightarrow \in = \frac{1}{4\pi}\frac{q_{1}q_{2}}{Fr^{2}} = C^{2}m^{- 2}N^{- 1}