Question

Shyam went to a Dussehra Mela with his father, there he saw a stall keeper in one of the food stalls has a large cylindrical vessel of base radius $15cm$ filled up to a height of $32cm$, with juice. He was selling juice in small cylindrical glasses of radius $3cm$ up to a height of $8cm$ and selling it for $Rs.3$ each.

Answer 1

Let us derived the given things to solve are Shyam and father went to Dussehra Mela.
He saw a stall keeper in there with the food stalls having the larger cylindrical vessels at the base of the radius is fifteen centimeters and height of the vessel is thirty-two centimeters with a juice too.
He selling the juice in the smallest of the cylindrical glasses of the radius is only three centimeters.
Formula used:
Volume of the cylinder vessel is $V = \pi {r^2}h$.

Complete step by step answer:

Since from the given question, the cylinder has a radius $15cm$ and height $32cm$.
For the glasses, the radius is given as $3cm$ and height is given as$8cm$. Also, the selling range is rupees three.
Thus, by applying the volume of the cylinder vessel we can able to solve this problem, which is $V = \pi {r^2}h$.
Where r is the radius of the given cylinder and h is the height of the given cylinder.
Therefore, we get by applying the values into the formula$V = \pi {r^2}h \Rightarrow (3.14){(15)^2}(32)$.
Thus, further solving we get$V = \pi {r^2}h \Rightarrow 22608c{m^3}$ (there are a total of three centimeters in the calculation, for the radius two and height contains one).
Hence for the volume of the cylinder glass can be written as$V = 22608c{m^3} \Rightarrow 0.226l$(converting the centimeters cube into the liter).
Therefore, He selling the juice in the smallest of the cylindrical glasses of the radius is only three centimeters is $3 \times 0.226l = 0.678l$. Hence which is the required answer.

Note:
Since there are a total of point six seven eight liters. And centimeters to liters is one liter equals to a thousand cubic centimeters.
Also with the height of the glasses is eight centimeters and they were selling at the rate of rupees three.
Since the radius is half of the diameter $r = \dfrac{d}{2}$ because the diameter is the overall measured for the given glasses.