Question
Question: Show that \(\vec a.(\vec b \times \vec c)\) is equal in magnitude to the volume of the parallelepipe...
Show that a.(b×c) is equal in magnitude to the volume of the parallelepiped formed on the three vectors a,b and c
Solution
The product of the area and altitude is known as the volume of the parallelepiped which is equal to the scalar triple product.Hence the vectors a, b and c are parallelepiped. The vector product of the two vectors is known as the area of the parallelogram.
Complete step by step answer:
When the components are perpendicular to each other then it is called the rectangular components of the vector.
In the above diagram, the position vectors are,
OA=a
⇒OB=b
⇒OC=c
We know that the parallelepiped volume is equal to the product of the parallelogram area and its height.
Hence we can write the volume of the parallelepiped =a.(b×c)……………….. (1)
Let us consider n is the unit vector which is perpendicular to the b and c. The n and c have the unique direction. So we can write,
b×c=bcsinθn^
Here the angle, θ=90∘. Finally,
b×c=bcn^ …….(2)
Using the equation (1) the parallelepiped volume is =a.(b×c)
Now we have to substitute the equation (2) into the equation (1) we get,
the parallelepiped volume is,
a.(bcn^)=abccosθn^
The n^ is the unit vector so the angle becomes, θ=0∘. Hence the parallelepiped volume becomes, abc. And, the given parallelepiped volume is abc.From this explanation a.(b×c) is equal to the parallelepiped volume.
Note: The three vectors are parallelepiped which means the vectors are present in the same plane which is a coplanar vector. In some particulars, the length of the vectors may be zero. The scalar is a component that has the only component which is the magnitude and the vector has the two components to specify which is a magnitude and the direction.