Solveeit Logo

Question

Mathematics Question on Vector Algebra

Show that the direction cosines of a vector equally inclined to the axes OX, OY, and OZ are 13\frac{1}{\sqrt 3},13\frac{1}{\sqrt 3},13\frac{1}{\sqrt 3}.

Answer

Let a vector be equally inclined to axes OX,OY,and OZ at angle a.
Then, the direction cosines of the vector are cos a, cos a, cos a.
Now,
cos2a+cos2a+cos2a=1
\Rightarrow3cos2a=1
\Rightarrowcos a=13\frac{1}{\sqrt 3}
Hence, the direction cosines of the vector which are equally inclined to the axes are 13\frac{1}{\sqrt 3},13\frac{1}{\sqrt 3},13\frac{1}{\sqrt 3}.