Question
Question: Show that \[A \cup B = A \cap B\] implies that \[A = B\]....
Show that A∪B=A∩B implies that A=B.
Solution
Here we will first assume an element of the set A and then we will form the condition between set A and set B in terms of the subset. Then we will assume an element belongs to set B and form the condition between set A and set B in terms of the subset. Then by comparing these conditions we will get the required expression.
Complete step-by-step answer:
Let x be an element which belongs to set A i.e. x∈A.
It means that x will also belong to the union of set A and set B i.e. x∈A∪B.
It is given that A∪B=A∩B which means x will also belong to the intersection of set A and set B i.e. x∈A∩B. By this, we can say that the element belongs to the set B also i.e. x∈B.
Therefore, by this, we can say that if the element belongs to set A, then it must belong to the set B which means set A is the subset of set B.
⇒A⊂B……………………..(1)
Similarly, let y be an element which belongs to set B or y∈B.
Therefore, it means that y will also belong to the union of set A and set B i.e. y∈A∪B.
It is given that A∪B=A∩B which means y will also belong to the intersection of set A and set B i.e. y∈A∩B. By this, we can say that the element belongs to set A also i.e. y∈A.
Therefore, by this, we can say that if the element belongs to set B, then it must belong to set A which means set B is the subset of set A.
⇒B⊂A……………………..(2)
From equation (1) and equation (2), we can say that set A equals the set B.
⇒A=B
Hence proved.
Note: Here we have to note that the set which includes all the elements from every set of data is called as union and denoted as A∪B. The set which includes only common terms between the given sets is called an intersection and generally denoted as A∩B. A subset is the set of the elements whose elements are present in the other main set. It is denoted as A⊂B. If the two sets are given and those two sets are the subsets to each other, then both the sets are equal.