Question

Show me structural formula of 5 Chloro - Hept - 3 -ene 6 yne

Answer 1

      Cl
      |
CH₃ - CH₂ - CH=CH - CH - C≡CH

Answer 2

The structural formula of 5 Chloro - Hept - 3 -ene 6 yne can be determined by breaking down the IUPAC name:

1. Parent Chain: "Hept" indicates a 7-carbon chain.
2. Multiple Bonds: "-3-ene" means a double bond between the 3rd and 4th carbon atoms. "-6-yne" means a triple bond between the 6th and 7th carbon atoms. When numbering, the multiple bonds are given the lowest possible locants. In this case, numbering from left to right gives 3-ene and 6-yne, which is correct.
3. Substituent: "5-Chloro" means a chlorine atom is attached to the 5th carbon atom.

Let's construct the structure step-by-step:

• Step 1: Draw the 7-carbon backbone.

C - C - C - C - C - C - C

• Step 2: Add the double bond at C3 and triple bond at C6.

C - C - C=C - C - C≡C (Numbering: 1 2 3=4 5 6≡7)

• Step 3: Add the chloro substituent at C5.

C - C - C=C - C(Cl) - C≡C

• Step 4: Add hydrogen atoms to satisfy carbon's valency (4 bonds).

  • C1: CH₃
  • C2: CH₂
  • C3: CH=
  • C4: =CH
  • C5: CH(Cl)
  • C6: C≡
  • C7: ≡CH

Combining these, we get the structural formula.

Structural Formula

      Cl
      |
CH₃ - CH₂ - CH=CH - CH - C≡CH

Explanation of the Solution

The name "5 Chloro - Hept - 3 -ene 6 yne" follows IUPAC nomenclature. "Hept" indicates a 7-carbon parent chain. "-3-ene" places a double bond between C3 and C4. "-6-yne" places a triple bond between C6 and C7. "5-Chloro" indicates a chlorine atom attached to C5. The chain is numbered to give the lowest possible locants to the multiple bonds as a set (3,6). Finally, hydrogen atoms are added to each carbon to satisfy its valency of four.