Shortest distance between lines (\frac{(x-5)}{4})=(\frac{(y-... | Mathematics | SolveeIt | Solveeit

Today, August 19

Question

Shortest distance between lines $\frac{(x-5)}{4}$ = $\frac{(y-3)}{6}$ = $\frac{(z-2)}{4}$ and $\frac{(x-3)}{7}=\frac{(y-2)}{5}=\frac{(z-9)}{6}$ is ?

A

$\frac{190}{37}$

B

$\frac{190}{\sqrt{756}}$

C

$\frac{37}{190}$

D

$\frac{756}{\sqrt{190}}$

Answer

$\frac{190}{\sqrt{756}}$

Explanation

Solution

The correct option is (B): $\frac{190}{\sqrt{756}}$