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Chemistry Question on Method of Preparation of Diazoniun Salts

Select the option with correct property -

A

[Ni(CO)4][Ni(CO)_4] and [NiCl4]2−[NiCl_4]^{2-} both diamagnetic

B

[Ni(CO)4][Ni(CO)_4] and [NiCl4]2−[NiCl_4]^{2-} both paramagnetic

C

[NiCl4]2−[NiCl_4]^{2-} diamagnetic, [Ni(CO)4][Ni(CO)_4] paramagnetic

D

[Ni(CO)4][Ni(CO)_4] diamagnetic, [NiCl4]2−[NiCl_4]^{2-} paramagnetic

Answer

[Ni(CO)4][Ni(CO)_4] diamagnetic, [NiCl4]2−[NiCl_4]^{2-} paramagnetic

Explanation

Solution

In [Ni(CO)4][\text{Ni}(\text{CO})_4], nickel is in the zero oxidation state and has a 3d103d^{10} electron configuration, leading to a fully paired electron configuration, making it diamagnetic.

In contrast, in [NiCl4]2−[\text{NiCl}_4]^{2-}, nickel is in the +2+2 oxidation state with a 3d83d^8 electron configuration. The chloride ligands are weak-field ligands and do not pair up the electrons, resulting in unpaired electrons and a paramagnetic nature.

Thus, the correct answer is:

[Ni(CO)4] is diamagnetic and [NiCl4]2− is paramagnetic.[\text{Ni}(\text{CO})_4] \text{ is diamagnetic and } [\text{NiCl}_4]^{2-} \text{ is paramagnetic.}