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Question: Select the correct order of basic nature: A. \(C{H_3}C{H^ - }_2 > C{H_2} = C{H^ - } > CH \equiv {C...

Select the correct order of basic nature:
A. CH3CH−2>CH2=CH−>CH≡C−>OH−C{H_3}C{H^ - }_2 > C{H_2} = C{H^ - } > CH \equiv {C^ - } > O{H^ - }
B. CH3CH−2>CH≡C−>CH2=CH−>OH−C{H_3}C{H^ - }_2 > CH \equiv {C^ - } > C{H_2} = C{H^ - } > O{H^ - }
C. CH3CH−2>OH−>CH≡C−>CH2=CH−C{H_3}C{H^ - }_2 > O{H^ - } > CH \equiv {C^ - } > C{H_2} = C{H^ - }
D. OH−>CH≡C−>CH2=CH−>CH3CH−2O{H^ - } > CH \equiv {C^ - } > C{H_2} = C{H^ - } > C{H_3}C{H^ - }_2

Explanation

Solution

Hint: We can approach this problem by finding out the acidic nature of the compounds and then we will get order of the basic nature of the ions. We know that the conjugate base is obtained by removing a proton from a compound.

Complete step by step solution:

The given ions are CH3CH−2,CH2=CH−,CH≡C−C{H_3}C{H^ - }_2,C{H_2} = C{H^ - },CH \equiv {C^ - } and OH−O{H^ - }. On addition of a proton (H+)\left( {{H^ + }} \right) to the given ions we have found that these compounds are CH3CH3,CH2=CH2,CH≡CHC{H_3}C{H_3},C{H_2} = C{H_2},CH \equiv CH and H2O{H_2}O. So we can find the order of acidic nature of the compounds. We know that a hydrogen tends to be acidic when it is attached to an electronegative atom or we can say that the conjugate base will be more stable on the localization of the negative charge on a more electronegative atom. The acidic nature of alkanes , alkenes and alkyne depends on the percentage s character. Alkanes used to be sp3s{p^3} hybridized so they have 25%25\% s-character similarly alkene possess 33.3%33.3\% s- character and alkynes possess 50%50\% s- characters. So their order of acidity is Alkynes > alkenes> Alkanes. Water will have less acidic nature than alkane, alkene and alkyne. Hence the order of acidic strength of the given compounds are H2O>CH≡CH>CH2=CH2>CH3CH3{H_2}O > CH \equiv CH > C{H_2} = C{H_2} > C{H_3}C{H_3}. We have studied that the conjugate base of a strong acid will be weak so the order of the given conjugate bases of the compounds will be CH3CH−2>CH2=CH−>CH≡C−>OH−C{H_3}C{H^ - }_2 > C{H_2} = C{H^ - } > CH \equiv {C^ - } > O{H^ - }. Hence option A is the correct order of basic nature.

Note: We know that the conjugate base of a stronger acid used to be a weak base and vice versa so here we have found the order of acidic nature of the given compounds and that order gives us the order of basic nature of compounds.