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Question: Select one correct statement. In the gas equation, \(PV=nRT\). (a)- n is the number of molecules o...

Select one correct statement. In the gas equation, PV=nRTPV=nRT.
(a)- n is the number of molecules of a gas
(b)- n moles of the gas has a volume V
(c)- V denotes the volume of one mole of the gas
(d)- P is the pressure if the gas when only one mole of gas is present

Explanation

Solution

If the ideal gas equation is written as PV=nRTPV=nRT then all the properties are for n mole of gas. If the ideal gas equation is written as PV=RTPV=RT then all the properties are for 1 mole of gas.

Complete step by step answer:
PV=nRTPV=nRTis an ideal gas equation that is used for calculating a certain property of the gas at specified conditions.
The ideal gas equation is directly by combining all the statements of gas laws like Boyle’s law, Charles Law, and Avogadro’s Law, which follows as:
Boyle’s law states that:
V1PV\propto \dfrac{1}{P} at constant T
Charles law states that:
VTV\propto T at constant P
Avogadro’s law states that:
VnV\propto n at constant T and P
In these, all statements n is the number of moles at V (volume) and P (pressure) of the gas at T (temperature).
So, by combining all these, we get:
V1P x T x nV\propto \dfrac{1}{P}\text{ x T x n}
Removing the proportionality, we introduce a constant known as gas constant and is denoted with R.
So, the equation is:
V=RTnPV=\dfrac{RTn}{P}
PV=nRTPV=nRT.

So, the correct answer is an option (b)- n moles of the gas have a volume V.

Note: If it is specified that the number of moles is 1 then, the equation is PV=RTPV=RT. It is also known as the equation of state. Some values of gas constant (R) taken are 0.0821 l atm deg1 mol10.0821\text{ l atm de}{{\text{g}}^{-1}}\text{ mo}{{\text{l}}^{-1}}, 8.314 x 107 ergs deg1 mol18.314\text{ x 1}{{\text{0}}^{7}}\text{ ergs de}{{\text{g}}^{-1}}\text{ mo}{{\text{l}}^{-1}}, 8.314 JK1 mol18.314\text{ J}{{\text{K}}^{-1}}\text{ mo}{{\text{l}}^{-1}} etc.