Solveeit Logo

Question

Question: Select incorrect reaction of lanthanide (Ln): A. \[{{Ln}} + {{{H}}_2}{{O}}\xrightarrow{{{\Delta }}...

Select incorrect reaction of lanthanide (Ln):
A. Ln+H2OΔLn(OH)3+H2{{Ln}} + {{{H}}_2}{{O}}\xrightarrow{{{\Delta }}}{{Ln}}{\left( {{{OH}}} \right)_{{3}}} + {{{H}}_2} \uparrow
B. Ln+N2ΔLnN{{Ln}} + {{{N}}_2}\xrightarrow{{{\Delta }}}{{LnN}}
C.Ln+S8Ln2S3{{Ln}} + {{{S}}_8} \to {{L}}{{{n}}_2}{{{S}}_3}
D. Ln+CLn4C{{Ln}} + {{C}} \to {{L}}{{{n}}_4}{{C}}

Explanation

Solution

The elements with atomic numbers from 58 (cerium) to 71 (lutetium) are known as lanthanoids. Lanthanoids lie in the f-block of the periodic table. The valence electron of all the lanthanides lies in the 4f orbital.

Complete step by step answer:
Lanthanoids when treated with water form hydroxides and liberate hydrogen gas. The lanthanide hydroxides are basic and ionic in nature. The balanced chemical reaction is as follows:
Ln+3H2OΔLn(OH)3+3H2{{Ln}} + 3{{{H}}_2}{{O}}\xrightarrow{{{\Delta }}}{{Ln}}{\left( {{{OH}}} \right)_{{3}}} + 3{{{H}}_2} \uparrow
Thus, the reaction Ln+H2OΔLn(OH)3+H2{{Ln}} + {{{H}}_2}{{O}}\xrightarrow{{{\Delta }}}{{Ln}}{\left( {{{OH}}} \right)_{{3}}} + {{{H}}_2} \uparrow is correct.
Lanthanides on heating with nitrogen form lanthanide nitrides. The balanced chemical reaction is as follows:
2Ln+N2Δ2LnN{{2Ln}} + {{{N}}_2}\xrightarrow{{{\Delta }}}{{2LnN}}
Thus, the reaction Ln+N2ΔLnN{{Ln}} + {{{N}}_2}\xrightarrow{{{\Delta }}}{{LnN}} is correct.
Lanthanides on heating with sulphur form lanthanoid sulphides. The balanced chemical reaction is as follows:
16Ln+3S88Ln2S3{{16Ln}} + 3{{{S}}_8} \to 8{{L}}{{{n}}_2}{{{S}}_3}
Thus, the reaction Ln+S8Ln2S3{{Ln}} + {{{S}}_8} \to {{L}}{{{n}}_2}{{{S}}_3} is correct.
Lanthanides on reaction with carbon form lanthanide carbides having formula Ln3C{{L}}{{{n}}_{{3}}}{{C}}, LnC2{{Ln}}{{{C}}_{{2}}} and Ln2C3{{L}}{{{n}}_2}{{{C}}_3}. The reaction is as follows:
Ln+CLanthanoid carbide{{Ln}} + {{C}} \to {\text{Lanthanoid carbide}}
Ln4C{{L}}{{{n}}_4}{{C}} is not formed in the reaction.
Thus, the reaction Ln+CLn4C{{Ln}} + {{C}} \to {{L}}{{{n}}_4}{{C}} is not correct.

Thus, the correct option is option (D).

Note:
The general electronic configuration of lanthanoids is 4f1145d016s24{f^{1 - 14}}\,5{d^{0 - 1}}\,6{s^2}. Lanthanides belong to the group three of the periodic table. The common oxidation state exhibited by all the lanthanides is +3. Some of the lanthanoids show +2 and +4 oxidation state.
The atomic and ionic radii of the lanthanoids decrease gradually with an increase in atomic number. This is known as lanthanoid contraction.
The early members of the lanthanoid series are very reactive and are similar to calcium. As the atomic number increases, lanthanoids behave similar to aluminium. Lanthanoids form carbides, hydrides, oxides, nitrides, hydrides, hydroxides and sulphides.