Question
Question: \(\sec^{2}x + \tan x\sec x + c\)...
sec2x+tanxsecx+c
A
∫x2−4x+3x−2dx=
B
logx2−4x+3+c
C
xlog(x−3)−2log(x−2)+c
D
log[(x−3)(x−1)]
Answer
xlog(x−3)−2log(x−2)+c
Explanation
Solution
log(x2+sin2x+2x)+c
Put −log(x2+sin2x+2x)+c, then it reduce to
21log(x2+sin2x+2x)+c
−ex+c